I think, all are familiar to that rates in bookmaker
offices happen following kinds:
- A normal level
- express
- System
- The conditional rate
About game by normal levels and expresss know everything,
game by the conditional rate is a little specific,
therefore we will disassemble it later. But here what I
have faced recently. What even the people, long enough
playing to bookmaker office, badly understand features
of game by system. Now I will try to tell about it. In
the form of questions and answers.
1) That such system?
Can glance in rules of any bookmaker office, and you
will meet there about such inscription. “The system is
the set of express representing full search of
variants of express of one size from the fixed set of
outcomes. It is characterised by the identical size of
the rate on each express (a system variant) and
identical quantity of outcomes in each express. At the
rate it is necessary to specify total of outcomes and
dimension of the express (a system variant) in system.
The prize on system is equal to the sum of prizes on the
expresss entering into system” (from game rules of one
known bookmaker office).
Similar it is possible to meet and in rules of other
offices. But here an ill luck. To understand this it is
difficult enough. Therefore I will try to explain same
the most simple accessible language.
We have solved, on what we will put. That is have
selected for game some matches. But here an ill luck. If
to play their normal levels what well to win, it is
necessary to put the decent sums of money for each match.
It is possible to arrive in another way: to generate the
express from the pleasant events. To put it is not
enough, but with the big factor. But in this case if any
rate loses, we absolutely will receive nothing. There is
also a third variant. To make of the selected events
some expresss. And if any event in one of expresss does
not play, we will receive 0 only on this express, and
the others will win.
But how to break rates on expresss? Can play doubles (expresss
from two events), tees (from three) or still somehow?
Further I will write, how it correctly to make. So, for
example we have chosen that all of us we will play rates
doubles. But what rates to include in what doubles? By
and large they after all all are equal (here to me
likely will object, after all there is a superrate which
100 % as will win. But remember how many time this your
superrate has not played?).
Here to us to the aid game by system also comes. At game
by system we speak. Here our events. Make of them
expresss. In each express include … (here we speak
dimension of system) events. In all possible
combination.
For example: our events:
1. A Torpedo - Spartak of M: the Victory of 2 commands
2. Krylja Sovetov – the Rotor: the Victory of 1 command
3. An Uralan - the M Locomotive: the Victory of 2
commands
Then the set of doubles for them will be:
1. (A Torpedo - Spartak of M: the Victory of 2 commands)
* (Krylja Sovetov – the Rotor: the Victory of 1 command)
2. (A Torpedo - Spartak of M: the Victory of 2 commands)
* (an Uralan - the M Locomotive: the Victory of 2
commands)
3. (Krylja Sovetov – the Rotor: the Victory of 1 command)
* (an Uralan - the M Locomotive: the Victory of 2
commands)
What does it give to us? That if the rate (a Torpedo -
Spartak of M has not played: the Victory of 2 commands)
and on 1 and 2 express we have received a prize 0. And
the third express has played. And we have won money.
That is in a case if we have united all 3 events in one
express, we would lose money. And in case of system even
in the presence of one not guessed event we will win
money.
2) I know that at game on system, it is necessary to
name on what system “How many from How many” I play. What
should I name?
Name quantity of events which you have selected for
rates. And how many events you would like to include in
each express from these events. The system 2 of 3 (we
have chosen 3 events and in each express have included
on 2 events) has been above disassembled. It is called
dimension of system.
3) That such quantity of variants in system?
That, how many expresss it is possible to make it, if
all events to break into expresss according to the set
dimension. For example, in system 2 from 3, it is
possible to make 3 expresss (on 2 events in everyone).
We assorted this case above.
4) What can be dimension of system? What restrictions
are on system?
Yes any. For example, 2 from 3, 7 from 9, 4 from 6 and
ect. But here it is necessary to consider the
following.
Offices can limit:
Quantity of events included in system.
The Maximum quantity of variants in system.
The Minimum sum on 1 variant of system
The Maximum factor of one express in system
For each bookmaker office these parametres. To find them
it is possible in rules.
And here for what they? In my opinion: "and" and are
connected with the out-of-date software of offices. In"that
players would put more money.“G”– what not to be ruined
if to players will carry.
5) What there are systems?
- Simple (what accept all offices, we have disassembled
them above)
- Difficult (what accept only the most advanced offices
(as I understand offices by which it allows to do their
software))
- Invented by various people – a set of ordinary rates
grouped in the different ways. wow! And how many their
everyones happens!
5) That such difficult system?
The most ridiculous in this question that to me set it
not only simple players, but also some bookmaker offices.
Even one very big known bookmaker office has set. Can
because I think, what they do not aspire to learn and
enter something new? So after all big …
The difficult system is a system each event in which can
consist of expresss. That is, for example, modifying
earlier considered example, earlier we had 3 events:
1. A Torpedo - Spartak of M: the Victory of 2 commands
2. Krylja Sovetov – the Rotor: the Victory of 1 command
3. An Uralan - the M Locomotive: the Victory of 2
commands
And we have wanted that the first event at us would be
not
“A Torpedo - Spartak of M: the Victory of 2 commands”,
and the express
1. (A Torpedo - Spartak) * (CSKA – the Ruby the Victory
of 1 command)
Then the system 2 of 3 will be:
1. ((A Torpedo - Spartak * (CSKA – the Ruby the Victory
of 1 command)) * (Krylja Sovetov – the Rotor: the
Victory of 1 command)
2. ((A Torpedo - Spartak * (CSKA – the Ruby the Victory
of 1 command)) * (an Uralan - the M Locomotive: the
Victory of 2 commands)
3. (Krylja Sovetov – the Rotor: the Victory of 1 command)
* (an Uralan - the M Locomotive: the Victory of 2
commands)
6) And for what these most difficult systems in general
are necessary? What to us for game of simple systems
will not suffice?
Difficult systems are convenient at game with small
factors. That is, for example, we have 2 events, at
which big factors. And some events, at which very small
factors. The optimal way in this case to make difficult
system 2 of 3. As first 2 events events with the big
factors will act. And the third event will be the
express from other events (those which with small
factors).
Let's continue to consider systems further. In general,
what purpose of game in bookmaker office? The majority
will tell – to win money! Also will be not right. The
overall objective, this money not to lose! As it is
known on statisticans lose 90. 92 % of players. At the
expense of them the others also live of 10 % of players
which win, and bookmaker offices.
Therefore today we will disassemble. As it is possible
not to lose, using systems.
We take such situation. We play system 2 of 3. Also have
guessed 2 outcomes. A question: We will get profit? Or
there will be at us losses. The answer: all depends on
factors which we played. If enough big (for system 2 of
3 = "> 1.73)" that we have won average factor of
advantageous events of system, to us will return money
back. If it is a bit less, we will a little lose.
Therefore for each system there is a so-called point of
break-even. We will result the table in which these
factors are described:
2 from 3 = ">" 1.73
3 from 4 = ">" 1.58
4 from 5 = ">" 1.49
5 from 6 = ">" 1.43
6 from 7 = ">" 1.38
7 from 8 = ">" 1.34
8 from 9 = ">" 1.31
That is, for example, playing system 8 of 9 and guessing
8 events, we will get profit if the won factors in
system are not less than 1.31.
Now. As to other systems.
2 from 4 = ">" (3 1.4(2) 2.45
3 from 5 = ">" (4 1.35(3) 2.15
2 from 5 = ">" (4 1.29(3) 1.8(2) 3.15
4 from 6 = ">" (5 1.32(4) 1.97
3 from 6 = ">" (5 1.26(4) 1.71(3) 2.71
2 from 6 = ">" (5 1.22(4) 1.58(3) 2.23(2) 3.87
5 from 7 = ">" (6 1.27(5) 1.85
4 from 7 = ">" (6 1.23(5) 1.63(4) 2.44
3 from 7 = ">" (6 1.20(5) 1.52(4) 2.06(3) 3.27
2 from 7 = ">" (6 1.21(5) 1.48(4) 1.91(3) 2.7(2) 4.7
6 from 8 = ">" (7 1.26(6) 1.74
5 from 8 = ">" (7 1.22(6) 1.56(5) 2.23
4 from 8 = ">" (7 1.19(6) 1.47(5) 1.93(4) 2.9
3 from 8 = ">" (7 1.17(6) 1.41(5) 1.77(4) 2.43(3) 3.83
2 from 8 = ">" (7 1.15(6) 1.35(5) 1.67(4) 2.15(3)
3.05(2) 5.3
What for figures stand in brackets? In brackets there is
a quantity of events guessed by us. That is 3 from 8 =
">" (5 1.77, it is necessary to understand that at game
in system 3 from 8 at guessing of 5 events we will be
returned by money if the average factor of the won
events is not less than 1.777 |